(2x-5)(2x^2+4x+3)=

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Solution for (2x-5)(2x^2+4x+3)= equation:


Simplifying
(2x + -5)(2x2 + 4x + 3) = 0

Reorder the terms:
(-5 + 2x)(2x2 + 4x + 3) = 0

Reorder the terms:
(-5 + 2x)(3 + 4x + 2x2) = 0

Multiply (-5 + 2x) * (3 + 4x + 2x2)
(-5(3 + 4x + 2x2) + 2x * (3 + 4x + 2x2)) = 0
((3 * -5 + 4x * -5 + 2x2 * -5) + 2x * (3 + 4x + 2x2)) = 0
((-15 + -20x + -10x2) + 2x * (3 + 4x + 2x2)) = 0
(-15 + -20x + -10x2 + (3 * 2x + 4x * 2x + 2x2 * 2x)) = 0
(-15 + -20x + -10x2 + (6x + 8x2 + 4x3)) = 0

Reorder the terms:
(-15 + -20x + 6x + -10x2 + 8x2 + 4x3) = 0

Combine like terms: -20x + 6x = -14x
(-15 + -14x + -10x2 + 8x2 + 4x3) = 0

Combine like terms: -10x2 + 8x2 = -2x2
(-15 + -14x + -2x2 + 4x3) = 0

Solving
-15 + -14x + -2x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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